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for the expansion of (x+4)^8, find the 6th term.
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\[\dbinom{8}{5}x^34^5\]
exponents must add to 8 \(\dbinom{8}{5}\) read "eight choose five" compute via compute \(\dbinom{8}{5}\) via \(\frac{8\times 7\times 6}{3\times 2}\) cancel first multiply last
okay so 56^3 (56 from the 8x7x6/3x2) and 4^5 multiply together for answer?
no nevermind that's wrong :/
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