Question

What is the equation of the line perpendicular to the line y = x – 2 that passes through the point (4,3)?

y = –x – 2
y = x + 6
y = –x + 12
y = –x – 12

Answer 1

The gradient of the required line*The gradient of the given line=-1
That is
m*m1=-1
m1=1
m*1=-1
m=-1
\[m=\frac{ y-y_1 }{ x-x_1 }\]
\[-1=\frac{ y-3 }{ x-4}\]
Can u find nw?