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What is a 3 digit even number
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its a 3 digit number divisible by 2
3 digit numbers number means we have to put 0-9 digit at 3 places....ABC at the position of A (first place) we can put any digit 1-9 not 0, otherwise it will not a 3 digit number, so by 9 ways at the position of B (second place) we can put 0-9 i.e by 10 ways... at the position of C (third place) we can put 0,2,4,6 or 8 i.e by 5 ways... so, total no. of digit = 9*10*5 = 450 Total no. of three digit even numbers =450
Hope that helps :)
copied and pasted from here : http://www.algebra.com/algebra/homework/Permutations/Permutations.faq.question.350843.html
Correct this helped me, so thought it would help the same :)
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