Question

a(t)=(2,0,6t) V(0)=(0,1,0) r(0)=(0,1,-3)
how to find unit tangent and unit normal vector
when t=1

Answer 1

i got v(t)=(2t,1,3t^2) is this right?

Answer 2

then i got T=(2t,1,3t^2)/(4t^2+1+9t^4)^(1/2) then i am stuck