Question

I'm new here and I need help with an additional mathematics course for GCSE's.
My first question is in the first reply to this, regarding logarithms.

Answer 1

Q. Using suitable substitutions, solve for x.
\[2e ^{x} = 7\sqrt{e ^{x}} - 3\]

Answer 2

e^x = t^2
you reduce your equation to
2t^2 = 7t -3

Answer 3

now solve the quadratic eqn

Answer 4

get it?

Answer 5

@him1618 Yes! Thanks a bunch! :D