Question

Suppose A and B are the end points of a diameter of the sphere whose equation is \[\x^{2}+y^{2}+(z+2)^{2}=1\]\. If A=(1,0,-2), then B is equal to

Answer 1

A) (0,1,-2) B) (0,0,-1) C) (-1,0,-2) D)(0,-1,-2)