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f(x)=x^2+x-56/x+3. what is the domain of f(x). Can someone help me with this asap? Thanks
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NOTE THAT: DENOMINATOR CANNOT BE ZERO
ok
So, can u find the value of x for which denominator is zero
no
so what is the domain and what is the equation of the vertical asymptote
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The denominator is x+3 So, x+3=0 x=-3
Thus, when x=-3 denominator is 0
got that
So, domain of f(x) is x belongs to all REAL number except -3
ok, so what is the equation of the vertical asymptote(s)
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