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\[2tanA=(1-\tan^2A)\cot56\]
hey theres a formula tan2A= 2tanA/1-tan^2A hence tan2A=cot56 tan2A.tan56=1 we also have another that if tanAtanB=1 then A+B=90 hence 2A+56=90 2A=90-56 A=34/2 =17 i hope its correct
aww.. it's correct!! thanks for the solution
and thanks for the help!
@eroshea :)))))))) welcome!!!!!
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