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Mathematics 20 Online
OpenStudy (anonymous):

If ysinx=a and ycosx=b find y in terms of a and b. :)

OpenStudy (anonymous):

\[y^2\sin^2x+y^2\cos^2x=a^2+b^2\]------->\[y=\sqrt{a^2+b^2}\]

OpenStudy (anonymous):

since \[\sin^2x+\cos^2x=1\]

OpenStudy (anonymous):

do u get it

OpenStudy (anonymous):

@sarihmanlapaz do u need any further explanation...or u understand this

OpenStudy (anonymous):

yes i get it! thanks for the help :)

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