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I have a total of 20 coins they are all dimes and quarters that total $11.50 how many of each coin do I have? x=#dimes y=#quarters if you have 20 coins then x+y=20 and if the amount of money totals (money per coin)x(# that coin) then 0.1x+0.25y=11.50 you then have two equations x+y=20 0.1x+0.25y=11.50 you can use these two eqns to solve for the number of each coin, x an y
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