Question

What is the 9th term of the geometric sequence where a1 = -8 and a6 = -8,192?


-327,680
-393,216
-458,752
-524,288

Answer 1

can you please provide me with the correct answer and how to solve it. thanks.

Answer 2

an= a1.r^{n-1}
so a6=(-8)r^5
find r from here.

Answer 3

a1= a = -8

a6= a.r^6-1 = -8192

-8.r^-5 = -8192

r= \[\sqrt[5]{8192/8} = \sqrt[5]{1024}= 4\]

Answer 4

okay

Answer 5

9th term will be a.r^8 u have a and r values...

Answer 6

so would the answer be -393,216