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what A did u get ?
-16.26020471 and then i substitute it to tan(A/2) which gave me -1/7 but i doubted my answer because of the 180<A<270, how will i do this? is my answer correct??
-16.2 is in 4th quadrant, not in 3rd
ow.. so there is another value for A? which will be in the 3rd quadrant?
yes.
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which i m trying to find
did you got it?? how??
sin(180-(-16.2))=sin(-16.2)=sin(196.2) so A=196.2
got that^ ?
waa!!.. -7 is the answer?? how did u arrived with the sin(180-(-16.2))?
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because sin(180-B)=sin B so i had sin(-16.2)=-7/25 i wanted to bring the angle in 3rd quadrant, so i used sin(180-B)=sin B
but when 270<A<360, is my answer correct?? -1/7?
yup. 4th quadrant.
owh.. thanks again..! :)) i have more questions.. i'll just post it :))
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