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OpenStudy (anonymous):
Let f(x)=x^2+2x-15 determine the values for x for which f(x)= -16
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OpenStudy (ajprincess):
since f(x)=-16 x^2+2x-15=-16 x^2+2x-15+16=0 x^2+2x+1=0 Can u find x nw?
OpenStudy (anonymous):
thanks :)
OpenStudy (ajprincess):
yw:)
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