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Question 6
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k^17 = k*k^16 so, k^8 comes out
If K^8 comes out then it will end up being A.
any doubts ?
\(\huge\sqrt{x^n}=x^{n/2}\)
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Now I'm confused
:P \(\huge \sqrt{k^{17}}=\sqrt{k.k^{16}}=k^8\sqrt{k}\)
I told you !
i just asked whether u had any doubts...
lol, you confused me for a second. I was like hey !
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hey :)
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