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Question 7
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you can break it up into \[\frac{ 6 }{ 2 } \times \frac{ g^3 }{ g^6} \times \frac {h^8}{h^6}\]
And simplify each of the terms
6/2 = 3
g ^ 3 / g ^ 6 = 1 / g ^ 3
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h ^ 8 / h ^ 6 = h ^ 2
then you put all the terms back together to get
\[\frac{ 3h^2 }{ g^3 }\]
Any questions?
Nope, thanks :D
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