Question

How do I make a piecewise funtion using latex?

Answer 1

or if anyones used something called "smart math", i'm very new to both.

Answer 2

like this?
\[ \large f(x)=\begin{cases}
x^2+1&\quad\hbox{if ...}\\
1/x&\quad\hbox{if ......}
\end{cases} \]

Answer 3

is this what u call picewise function?

Answer 4

yes, exactly

Answer 5

\begin{cases}
x^2+1&\quad\hbox{if ...}\\
1/x&\quad\hbox{if...}
\end{cases}

Answer 6

can u copy the code.
i don't know how to make the code appear

Answer 7

I can't copy the code I don't think. Thanks guys.

Answer 8

To copy the code, right click the math, move to "Show Math As" and then click on "TeX Commands" Then copy paste the text that appears in the new window.

Answer 9

can u download that?

Answer 10

@helder_edwin yes, got the code from the attachment

Answer 11

thanks for the tip @KingGeorge, works great!

Answer 12

@helder_edwin how do you do less than or equal to?

Answer 13

"\leq" gives you \(\leq\)
"\geq" gives you \(\geq\)

Answer 14

thanks!

Answer 15

u r welcome

Answer 16

this might be of help

Answer 17

\large f(x)=\begin{cases} 2-x &\quad\hbox{if x < -1}\\ x^3 + x^2 +3 &\quad\hbox{if x \leq 0 }\\x/(x^2+1) &\quad\hbox{if x > 0 } \end{cases}

Answer 18

u have to write
"\hbox{if $x\leq0$}"
or
\[\verb"\hbox{if \(x\leq0\)}"\]

Answer 19

thanks so much, worked great

Answer 20

u r very welcome