Question

Solve: 4^1-2x=2

Answer 1

ok.... rewite your equation

\[(2^2)^{1 - 2x} = 2^1\]

use the power of a power law

\[(x^a)^b = x^{a \times b}\]

so you will have

\[2^{2 - 4x} = 2^1\]

all you need to do now is solve

2 - 4x = 1

since the bases are the same