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Mathematics 15 Online
OpenStudy (anonymous):

for y=x^2-10 do the following A) Sketch a graph of the equation B) Identify the vertex C)Compare the graph of y=f(x) to the graph of y=x^2 (state any transformations used)

OpenStudy (anonymous):

First, does the graph open up or down?

OpenStudy (anonymous):

up?

OpenStudy (anonymous):

O wait no - 10 so down right?

OpenStudy (anonymous):

No, now when you look for whether the graph opens up or down you're looking at the "quadratic term". The quadratic term dominates everything else. The quadratic term is the (x^2) one.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

So is the quadratic term positive or negative?

OpenStudy (anonymous):

positive

OpenStudy (anonymous):

Excellent, so the parabola opens up. Now here, look at what happens when x is 0. What is y?

OpenStudy (anonymous):

-10? Sorry not verygood at this

OpenStudy (anonymous):

No you got it. So y is -10 when x is 0. And the graph opens up. |dw:1348357613832:dw|

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