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solve for x: (log[3](log[3]x))=-3
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\(\huge if \quad log_ax=b \quad then \quad a^b=x\) so what will be (log[3](log[3]x))=-3 ?
so u get (-3)^3 = ?
x=-3^3 =>-27? i still don't understand what happens to the other log[3]x?
(log[3](log[3]x))=-3 gives u log[3]x=(-3)^3 using definition of log i mentioned in 1st comment. got this.?
oh okay I got it.
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so whats your final answer ?
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