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if 82degrees + 0.35x = arctan(cot 0.45x) , what is x?
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but how would u proceed....? not the best way, i think.
yup u r right. that's vat I am thnkng.
ArcTan[Cot[y]] = y - Pi/2 arctan(cot 0.45x) = 0.4x -90
oh, wait. tan(90-y)= cot y, right ? so arctan(cot y) should be 90-y arctan(cot 0.45x) =90-0.4x
0.45x
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90-0.45x=82+0.35x
u getting x=10 ?
yap !! :)) thanks!
messed up last problem, atleast could solve this.....
totally fine :)) i'll answer that later on
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U r very brilliant @hartnn
that's right!
thanks :D
yw nd u deserv that compliment:)
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