Question

please answer :)

Answer 1

\[if x+y=90, then \frac{ sinx tany }{ siny tanx } is equal \to?\]

Answer 2

u want answer in terms of x or y ?

Answer 3

the possible answers are
a. tanx b.1/tanx c.-tanx d. -1/tanx

Answer 4

given
\[x+y=90\]
\[\frac{\sin x \tan y}{\sin y \tan x}\ \ \ \ \ \ \ =\]
write all in terms of
y=90-x
@eroshea
what's sin (90-x)??

Answer 5

cos x?

Answer 6

good, so sin y=sin (90-x)=cos x
similarly change tan y in terms of x

Answer 7

i'm confused @.@

Answer 8

tan y=tan (90-x)=??

Answer 9

that's cot y = (tan 90-x)

Answer 10

good so \[\frac{\sin x \tan y}{\sin y \tan x}\ \ \ \ \ \ \ =\frac{\sin x \cot x}{\cos x \tan x}\ \ \ \ \ \ \ = ?\]
Can you simplify this now?

Answer 11

tanx?

Answer 12

owh.. 1/tanx maybe?

Answer 13

check again, are you sure?

Answer 14

what i got was cosx/sinx =cotx or 1/tanx

Answer 15

you're correct :)

Answer 16

thanks! :))