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sin(x+10deg)=cos3x then x=?
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can you help me ?
u know the identity sin(90-A)=cos A ?
so write cos 3x as sin (90-3x) now u have sin(x+10) = sin (90-3x) so x+10 = 90-3x can u solve this for x ?
Note that, \[x + 10 + 2n \pi = 90 - 3x\]
i get 20 :)) thank you so much
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yup, its 20, do u need general solution in terms of n?
yes yes :)
x+10+2nπ=90−3x 4x=80-2nπ x=20-nπ/2
oh i get it. thanks but can i have 1 more question?
If cosA= -15/17 and A is in quadrant III, find cos 1/2A
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