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Mathematics 6 Online
OpenStudy (anonymous):

solve for x. lnx + ln(x-1) = 1

Parth (parthkohli):

\[\ln\left| x(x - 1)\right| = 1\]\[\log_{\large e}x(x - 1) = 1 \\ \\ e = x(x - 1) \]

OpenStudy (jiteshmeghwal9):

|dw:1348496516336:dw|

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