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Explain to me what I'm supposed to do in this DiffEq problem. (see attached pic)
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So I found out that it's unstable, and got a general solution of t+c=ln(x-4), now what?
x=Be^t+4, e^c=B
Where are you getting b's from? And I need explanations not answers.
add e left and right, it will become e^ln(x-4)=e(t+c) e^ln whatever=whatever, thus ln(x-4)=e^t*e^c,
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ops should be x-4 only
Right, I know how natural logs work, I just don't know what the goal of this problem is.
oic, forget to read the statement.. haha
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