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Mathematics 19 Online
OpenStudy (anonymous):

lim x approaches a (a^3-x^3)/(a-x)

OpenStudy (anonymous):

hint factor out num using cubes difference\[a^3-x^3=(a-x)(a^2+ax+x^2)\]

OpenStudy (precal):

then you should see that something cancels out and then sub x=a for x

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