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what is the product of sqrt 2 (6b sqrt 16 -2b)
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no this. @Hero
\[\sqrt{2}(6b \sqrt{16} - 2b)\]
Okay, so distribute the \(\sqrt{2}\)
Actually, it would probably be much easier for you to reduce \(\sqrt{16}\)
First, before doing anything else, just reduce \(\sqrt{16}\)
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Actually, I'll just post the steps I came up with
\[\sqrt{2}(6b \sqrt{16} - 2b)\] Reduce \(\sqrt{16} = 4\) to get: \[\sqrt{2}(6b \dot\ 4 - 2b)\] Multiply 6 x 4 to get 24: \[\sqrt{2}(24b - 2b)\] Subtract 24b - 2b to get 22b: \[\sqrt{2}(22b)\]
And you can re-write that as \(22b\sqrt{2}\)
Which is one of your answer choices
thanks so muchhh @hero
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