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Find the sum of three consecutive odd integers if the sum of the first two integers is equal to twenty-four less than four times the third integer.
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2n + 2 = 4(n+4) - 24
sorry half my answer deleted itself there
let the first odd number = n the sum, s, is given by: n + n+2 + n+4 = s the last bit of information tells us n + n+2 = 4(n+4) - 24
solve the last equation to find n, then use this value to find s
Thank you SO much! :D!
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no problem :)
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