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Mathematics
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(1,-1), (-4, 5) I'm trying to find the equation of the line that passes through the points
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find the slope first which is y2 - y1divided by x2 - x1, and than put it in slope form y=mx+b.
slope would be -.5
5-(-1) = 5+ 1 = 6 and then over -4 - 1 = -5 so the slope would be -6/5
m = (5-(-1))/(-4-1) so m= .5
then take any point and plug it into y = mx + b and solve for b. so take (1,-1) and plug it in -1 = (-6/5)(1) + b -1 = -6/5 + b b = -1 + 6/5 = 1/5
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what's 5 - (-1)?
it's 6..., and -4 -1 is -5
that negative makes the negative in the bracket a positive.
so your finished equation will be y = -6/5x + 1/5
Oh I wrote it down without the changed sign.
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