Ask your own question, for FREE!
OCW Scholar - Single Variable Calculus 8 Online
OpenStudy (anonymous):

can someone help me with the following equation: lim cos x/sin2x approaching pi/2

OpenStudy (anonymous):

sin2x = 2sinxcosx so lim cosx/sin2x = lim cosx/2sinxcosx = lim 1/2sinx = 1/2

OpenStudy (anonymous):

Thanks a lot, appreciated!!!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!