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OpenStudy (anonymous):
can someone help me with the following equation: lim cos x/sin2x approaching pi/2
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OpenStudy (anonymous):
sin2x = 2sinxcosx so lim cosx/sin2x = lim cosx/2sinxcosx = lim 1/2sinx = 1/2
OpenStudy (anonymous):
Thanks a lot, appreciated!!!!
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