Question

a volleyball is tossed from a window at 6 m/s (32 degree below horizonta)and it lands 3.4 s later.calculate a)height of window b)velocity of volleyball at ground level

Answer 1

\[V=\sqrt{((Vo*\cos(\alpha))^2 + (Vo*\sin(\alpha)+g*t)^2)}\]\[H=Vo*\sin(\alpha)*t + g*t^2/2\]