Question

If
f(x) = 8x2 − x3,
find f'(2) and use it to find an equation of the tangent line to the curve
y = 8x2 − x3
at the point (2, 24).

Answer 1

f'(x)=16x-3x^2
plug in 2 and you get 20.

Answer 2

now equation of a tangent line is y-y1=m(x-x1)
so you have: y-24=20(x-2) that's it

Answer 3

thanks!!!(: