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Physics 22 Online
OpenStudy (anonymous):

An object accelerates from rest to 85 m/s over a distance of 36m . What acceleration did it experience ?

OpenStudy (anonymous):

100m/s^2

OpenStudy (anonymous):

using Vf=2a(deltaX)

OpenStudy (anonymous):

this is only because it started from rest

OpenStudy (anonymous):

Rest V1 = 0 V2 = 85 m/s distance = 36m acceleration = ? best equation : v2² = v1² + 2ad rearrange for acceleration and you get A = v2² - v1² / 2d

OpenStudy (anonymous):

Daboss 123 u forgot the () so A = (v2² - v1² )/ 2d

OpenStudy (anonymous):

Thank you soooooo much !! 😄

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