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the perimeter of a triangle cannot be more thAN 46 FT. If one side of a triangle is twice as long as the second side and the third side is 19ft long. Find the longest possible values for the other two sides
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P = a + b + c if a = 19, we know that b=2c. So: 46 = 19 + b + c --> 27 = 2c+c 27 = 3c --> c = 9 since b=2c, b=2(9) = 18. 9 and 18 are your answers.
awesome thank you taylor
yw
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