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how do you factor 1-8a^6?
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here's a hint. the formula for difference of two cubes is \[\huge a^3 - b^3 \implies (a-b)(a^2 + ab + b^2)\] does that help? or do you need more help?
ya i still dont understand- it says that in my book but i dont understand it.
here's another hint \[\huge 1 \implies 1^3\] \[\huge 8a^6 \implies (2a^2)^3\] do you get what i'm implying?
alright thanks so you just find the cubed root of the numbers which represent to a and b and just plug it into the equation right?
right
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