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Mathematics 15 Online
OpenStudy (anonymous):

16u^4v^3

OpenStudy (anonymous):

\[16u^4v^3 \] this?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

whats there to solve then?

OpenStudy (anonymous):

the square root of 16u^4v^3

OpenStudy (anonymous):

\[(16u^4v^3 )^\frac{ 1 }{ 2 }\] will give you \[4u^2v^\frac{ 3 }{ 2 } \]

OpenStudy (anonymous):

where did you get the 1/2

OpenStudy (anonymous):

square root can also be written as 'to the power 1/2' ;)

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