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Hose A can fill a certain vat in 3 hours. After 2 hours of pumping, hose A is turned off. Hose B is then turned on and completes filling the vat in 3 more hours. How long would it take hose B to fill the vat alone?
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Okay this is a toughie.
I think the answer is nine but i dont know how to set up the equation
So hose A fills a vat in 3 hour. That means, in 2 hours, it fills 2/3 of a vat. 1/3 of a vet left and it takes hose B 3 hours to fill 1/3. 3 1/3's make a whole vat. So you multiply 3 by 3 get 9
Sorry I don't know how to make an equation with that
Maybe 1/9b=1
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haha
sorry
Solve the following for x, the time it takes b to fill the vat alone.\[\frac{1/3}{3}=\frac{1}{x}\]x = 9 hours
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