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Mathematics 22 Online
OpenStudy (anonymous):

Evaluate arcos sqroot 3/2

OpenStudy (nubeer):

\[\cos^{-1} (\sqrt{3}/2)\] = 30

OpenStudy (anonymous):

\[\arccos (cannot find \square \root button, but \square \root of 3/2)(\]

OpenStudy (anonymous):

so it's the inverse of COS?

OpenStudy (nubeer):

yes..arcos =inverse of cos

OpenStudy (anonymous):

The answer should be without a calculator.

OpenStudy (anonymous):

So can I use the unit circle?

OpenStudy (anonymous):

I just noticed it should be in radians.

hartnn (hartnn):

yup, use unit circle, u will find it to be pi/6

OpenStudy (nubeer):

u can fine it in degree.. and then multiply it with pi/180.. it will give answer in radian

OpenStudy (anonymous):

just to understand, how do I find the degree without a calculator?

OpenStudy (mayankdevnani):

need any help @Butler

OpenStudy (mayankdevnani):

i will give you hint http://answers.yahoo.com/question/index?qid=20090227105545AAnqVyR

OpenStudy (anonymous):

Thanks that's a great link. It helped me link the process together better!

OpenStudy (mayankdevnani):

welcome......

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