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4(x+2)-(x+3)=8 Please explain to me
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first multiply 4 with numbers inside 4x +8 - x+3 = 8 3x +11 = 8 3x = -3 x =-1
4(x+2) 4x+8 so, (4x+8)-(x+3)=8 4x+8-x-3=8 3x+5=8 3x+5-5=8-5 ....(transposition) 3x=3 x=3/3=1
4(x+2)-(x+3)=8 4x + 8 - x - 3 = 8 4x - x = 8 - 8 + 3 3x = 3 x = 1
Thanks all of you!
yw :)
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