Question

if an aroma of vanillin fills a room, having the dimensions of 12ftx10.5ftx10.0ft. if the density is 2.4x10^-11g/L how many kilograms of vanillin are in the room?

Answer 1

Density formula:
\[\rho=\frac{m}{V}\]
\[m=\rho V\]
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Volume= 12x10.5x10.0=1260ft^3= 35679 liters
\[m=\rho V\]

\[m=( 2.4x10^{-11}g/L )(35679L) \]
\[m=8.56\times 10^{-7}g=8.56 \times 10^{-10}kg\]

Answer 2

hey thanks- can you explain how you get from cubic feet to liters?

Answer 3

You either remembering it or from a table of conversions,
1 Cubic Feet = 28.32 Liters
You can arrange it so that the cubic feet is at the bottom when you multiply, to cancel the cubic feet. You want liters here, so:
\[1280~ ft^3 \times \frac{28.32~liters}{1~Cubic~feet}=35679~liters\]

Answer 4

got it. thank you so much!