find the area of the surface generated by revolving the curve about the indicated axis.
x=3(4-y)^(1/2) 0is less than or equal to y, and y is less than or equal to (15/4), about the y axis

Question

find the area of the surface generated by revolving the curve about the indicated axis.
x=3(4-y)^(1/2)    0is less than or equal to y, and y is less than or equal to (15/4), about the y axis

amistre64 · Answer

id prolly rewrite as y in terms of x

chrisplusian · Answer

but then don't you have to change the bounds of integration?

amistre64 · Answer

you have to keep them in mind yes, but thats not really tough to do

4 - 9x^2 = y

amistre64 · Answer

1/9  not 9

chrisplusian · Answer

ok I was scratching my head

amistre64 · Answer

|dw:1348515272096:dw|i think they will look something like this if graphed