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find the area of the surface generated by revolving the curve about the indicated axis. x=3(4-y)^(1/2) 0is less than or equal to y, and y is less than or equal to (15/4), about the y axis
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id prolly rewrite as y in terms of x
but then don't you have to change the bounds of integration?
you have to keep them in mind yes, but thats not really tough to do 4 - 9x^2 = y
1/9 not 9
ok I was scratching my head
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|dw:1348515272096:dw|i think they will look something like this if graphed
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