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Suppoese T is self-adjoint. Show that T^2(v)=0 implies T(v)=0. Using this prove that T^n(v)=0 also implies that T(v)=0 for n>0
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if T(v)#0 -> T*(v)=T(v)#0 ->T^2(v)=T(v).T*(v)#0
because T.T*=detT.I & detT #0
induction: for n=2 is ok suppose for k is true then try to show for k+1 is true
why detT#0 ?
because detT*=detT^m-1=detT -> detT^m=1 or detT#0
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if m=odd detT=1 and if m=even detT=+-1
done?
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