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Physics 17 Online
OpenStudy (anonymous):

A marble is projected vertically up by a spring gun, and reaches the maximum height of 9.8m. What is the initial speed of the marble? How long did it take the marble to reach maximum height?

OpenStudy (anonymous):

\[V _{f}^{2} = 0 = V _{i}^{2} -2*g*9.8m\]

OpenStudy (anonymous):

what is the final velocity though?

OpenStudy (anonymous):

zero

OpenStudy (anonymous):

:O ok hold on I would like to see if I get it right

OpenStudy (anonymous):

192.08 m/s?

OpenStudy (anonymous):

= Vi^2

OpenStudy (anonymous):

so...

OpenStudy (anonymous):

13.85

OpenStudy (anonymous):

m/s

OpenStudy (anonymous):

take the....

OpenStudy (anonymous):

______ root of both sides...

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

sure:)

OpenStudy (anonymous):

got the time part figured out?

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