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A marble is projected vertically up by a spring gun, and reaches the maximum height of 9.8m. What is the initial speed of the marble? How long did it take the marble to reach maximum height?
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\[V _{f}^{2} = 0 = V _{i}^{2} -2*g*9.8m\]
what is the final velocity though?
zero
:O ok hold on I would like to see if I get it right
192.08 m/s?
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= Vi^2
so...
13.85
m/s
take the....
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______ root of both sides...
yes
thanks
sure:)
got the time part figured out?
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