Question

The length of a rectangle is more than twice its width . It's perimeter is between 300 and 600. Find all possible values of its width.

Answer 1

let width(w)=x
length(l)=2x
300 < perimeter(p) < 600, so
300 < 2(l+w) < 600
divided by 2
150 < l+w < 300
150 < 2x+x < 300
150 < 3x < 300
solve for x !