Two parallel plates, each having area A = 3557 cm2 are connected to the terminals of a battery of voltage Vb = 6 V as shown. The plates are separated by a distance d = 0.59 cm. The battery is now disconnected from the plates and the separation of the plates is doubled ( = 1.18 cm). What is the energy stored in this new capacitor?

Question

anonymous · Answer

what you should do first is calculate the capacitances in the 2 cases. Do you know how to do that?

anonymous · Answer

Yes I actually just got tha question thank you though.

anonymous · Answer

yw :)