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The coefficients of friction between a block of mass 2.0 kg and a surface are μs = 0.60 and μk = 0.25. Assume the only other force acting on the block is that due to gravity. What is the magnitude of the frictional force (in newtons) on the block if the block is at rest and the surface is inclined at 19o? Use g = 9.79 m/s2
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\[|dw:1348535040787:dw|\]
if the block is @ rest then....Static Friction acts on it..... \[Fs = \mu* mg* \cos \theta\]
\[\mu = 0.6\] because......it is Static Friction...)
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