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f(x)=3xh(x) h(2)=-1 h ' (2)=-1 Find f ' (2)
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\[\bf f' = 3(xh)' = 3(x'h + xh')\]
Soo f' = 3h + 3xh'
so f'(2) =3h(2) + 3xh'(2) = ?....
= -3 + 3*2*(-1) = -9
Makes sense. Thanks, Mikael.
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