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simplify the expression. 3-4t/8t-6
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\[\frac{ 3-4t }{ 8t-6 }\]Is that the question?
yes
try factoring out a -2 from the denominator and let me know what you think?
\[3-4t \div-4t+3\]
\[\frac{ 3-4t }{ -2(3-4t) }\]Now what do you see?
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so that gives you -1/2
corrrecctttt!!
Do you want me to explain how i thought to do that?
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