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If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 48 ft/sec, its height after seconds is s(t)=48+48t-16t^2. I got: What is the maximum height the ball reaches? 84feet But I need help on... What is the velocity of the ball when it hits the ground (height 0)?
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\[s(t) = 48+48t - 16t^2\\ s(t) = 48+ 32t \\32t = 48\]
3/2?
uhm, no 48/32 is 3/2?
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