Question

If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 48 ft/sec, its height after seconds is s(t)=48+48t-16t^2.

I got:
What is the maximum height the ball reaches?
84feet

But I need help on...
What is the velocity of the ball when it hits the ground (height 0)?

Answer 1

\[s(t) = 48+48t - 16t^2\\ s(t) = 48+ 32t \\32t = 48\]

Answer 2

3/2?

Answer 3

uhm, no 48/32 is 3/2?