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Given the following table: x= 0.0036, 0.0046, 0.0056, 0.0066, 0.0076 f(x)= 0.96812277, 0.58218317, 0.47885736, 0.65840989, -0.35969788 Calculate the value of f′(0.0056) = to two places of accuracy.
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