Question

factorable trinomials
whose first term is x^2 and last term is -16.
any more suggestions?

Answer 1

i would write
\[x^2-16=(x+4)(x-4)\] but i am not exactly sure what the question is

Answer 2

@satellite73 TRINOMIAL = 3.

Answer 3

list all pairs of factors of 16
1,16
2,8
4,4

now assign different signs (because the last term -16 is negative)
-1, +16 and +1,-16
-2, +8 and +2, -8
and +4, -4 (of course -4 , +4 is the same thing)

now you have all factors that will work
first set gives (x-1)(x+16) and (x+1)(x-16)

feel free to finish...